Base | Representation |
---|---|
bin | 111100100010101100… |
… | …0101111000101101001 |
3 | 110102120211122101010100 |
4 | 1321011120233011221 |
5 | 4112231330143423 |
6 | 135421024340013 |
7 | 12251563244325 |
oct | 1710530570551 |
9 | 412524571110 |
10 | 130013131113 |
11 | 50158028798 |
12 | 21245174609 |
13 | c34c821618 |
14 | 6415126985 |
15 | 35ae0a9343 |
hex | 1e4562f169 |
130013131113 has 24 divisors (see below), whose sum is σ = 197371661760. Its totient is φ = 82310453280.
The previous prime is 130013131091. The next prime is 130013131217. The reversal of 130013131113 is 311131310031.
It is not a de Polignac number, because 130013131113 - 29 = 130013130601 is a prime.
It is a super-2 number, since 2×1300131311132 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (130013131013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2230518 + ... + 2288063.
It is an arithmetic number, because the mean of its divisors is an integer number (8223819240).
Almost surely, 2130013131113 is an apocalyptic number.
It is an amenable number.
130013131113 is a deficient number, since it is larger than the sum of its proper divisors (67358530647).
130013131113 is a wasteful number, since it uses less digits than its factorization.
130013131113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4518749 (or 4518746 counting only the distinct ones).
The product of its (nonzero) digits is 81, while the sum is 18.
Adding to 130013131113 its reverse (311131310031), we get a palindrome (441144441144).
The spelling of 130013131113 in words is "one hundred thirty billion, thirteen million, one hundred thirty-one thousand, one hundred thirteen".
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