Base | Representation |
---|---|
bin | 11101100011111100001111… |
… | …111111100000110101011011 |
3 | 122001100010212002000210120022 |
4 | 131203330033333200311123 |
5 | 114020114040132400034 |
6 | 1140303130015421055 |
7 | 36246100606131446 |
oct | 3543741777406533 |
9 | 561303762023508 |
10 | 130013223325019 |
11 | 38476331147011 |
12 | 126b952552478b |
13 | 577126acb9b68 |
14 | 241696045c65d |
15 | 1006e20410b2e |
hex | 763f0ffe0d5b |
130013223325019 has 2 divisors, whose sum is σ = 130013223325020. Its totient is φ = 130013223325018.
The previous prime is 130013223324961. The next prime is 130013223325033. The reversal of 130013223325019 is 910523322310031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130013223325019 - 236 = 129944503848283 is a prime.
It is a super-2 number, since 2×1300132233250192 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 130013223325019.
It is not a weakly prime, because it can be changed into another prime (130013223325099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65006611662509 + 65006611662510.
It is an arithmetic number, because the mean of its divisors is an integer number (65006611662510).
Almost surely, 2130013223325019 is an apocalyptic number.
130013223325019 is a deficient number, since it is larger than the sum of its proper divisors (1).
130013223325019 is an equidigital number, since it uses as much as digits as its factorization.
130013223325019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 29160, while the sum is 35.
The spelling of 130013223325019 in words is "one hundred thirty trillion, thirteen billion, two hundred twenty-three million, three hundred twenty-five thousand, nineteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •