Search a number
-
+
1300135534657 = 2854945540493
BaseRepresentation
bin10010111010110110000…
…111011110000001000001
311121021212200101022211021
4102322312013132001001
5132300134144102112
62433135104345441
7162634366463221
oct22726607360101
94537780338737
101300135534657
11461425684403
1218bb84915281
13957aa20016b
1446cd958a081
1523c45c98907
hex12eb61de041

1300135534657 has 4 divisors (see below), whose sum is σ = 1300181103700. Its totient is φ = 1300089965616.

The previous prime is 1300135534619. The next prime is 1300135534673. The reversal of 1300135534657 is 7564355310031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 478821096961 + 821314437696 = 691969^2 + 906264^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300135534657 - 211 = 1300135532609 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1300135534157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22741698 + ... + 22798795.

It is an arithmetic number, because the mean of its divisors is an integer number (325045275925).

Almost surely, 21300135534657 is an apocalyptic number.

It is an amenable number.

1300135534657 is a deficient number, since it is larger than the sum of its proper divisors (45569043).

1300135534657 is an equidigital number, since it uses as much as digits as its factorization.

1300135534657 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45569042.

The product of its (nonzero) digits is 567000, while the sum is 43.

The spelling of 1300135534657 in words is "one trillion, three hundred billion, one hundred thirty-five million, five hundred thirty-four thousand, six hundred fifty-seven".

Divisors: 1 28549 45540493 1300135534657