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130014114 = 2321669019
BaseRepresentation
bin1111011111111…
…01101110100010
3100001122101211120
413233331232202
5231240422424
620522353110
73136046616
oct757755642
9301571746
10130014114
116743158a
123765b796
1320c22039
14133a5346
15b632a79
hex7bfdba2

130014114 has 8 divisors (see below), whose sum is σ = 260028240. Its totient is φ = 43338036.

The previous prime is 130014107. The next prime is 130014121. The reversal of 130014114 is 411410031.

It is an interprime number because it is at equal distance from previous prime (130014107) and next prime (130014121).

It is a sphenic number, since it is the product of 3 distinct primes.

130014114 is an admirable number.

It is a junction number, because it is equal to n+sod(n) for n = 130014093 and 130014102.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10834504 + ... + 10834515.

It is an arithmetic number, because the mean of its divisors is an integer number (32503530).

Almost surely, 2130014114 is an apocalyptic number.

130014114 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130014114 is a wasteful number, since it uses less digits than its factorization.

130014114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21669024.

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 130014114 is about 11402.3731740371. The cubic root of 130014114 is about 506.5980342362.

Adding to 130014114 its reverse (411410031), we get a palindrome (541424145).

The spelling of 130014114 in words is "one hundred thirty million, fourteen thousand, one hundred fourteen".

Divisors: 1 2 3 6 21669019 43338038 65007057 130014114