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13001412312443 = 88845714633699
BaseRepresentation
bin1011110100110010000010…
…0011111111110101111011
31201000220220210000102201202
42331030200203333311323
53201003343022444233
643352433311204415
72511215055144362
oct275144043776573
951026823012652
1013001412312443
114162960338a65
12155b91681670b
13734049458159
1432d3b38207d9
151782e365ebe8
hexbd3208ffd7b

13001412312443 has 4 divisors (see below), whose sum is σ = 13001427834600. Its totient is φ = 13001396790288.

The previous prime is 13001412312437. The next prime is 13001412312451. The reversal of 13001412312443 is 34421321410031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13001412312443 - 218 = 13001412050299 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13001412312143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6428393 + ... + 8205306.

It is an arithmetic number, because the mean of its divisors is an integer number (3250356958650).

Almost surely, 213001412312443 is an apocalyptic number.

13001412312443 is a deficient number, since it is larger than the sum of its proper divisors (15522157).

13001412312443 is an equidigital number, since it uses as much as digits as its factorization.

13001412312443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15522156.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 13001412312443 its reverse (34421321410031), we get a palindrome (47422733722474).

The spelling of 13001412312443 in words is "thirteen trillion, one billion, four hundred twelve million, three hundred twelve thousand, four hundred forty-three".

Divisors: 1 888457 14633699 13001412312443