Search a number
-
+
1300142121 = 32112053937
BaseRepresentation
bin100110101111110…
…1001100000101001
310100121110001200220
41031133221200221
510130314021441
6333002320253
744135011545
oct11537514051
93317401626
101300142121
11607995023
123034b9089
13179487885
14c495aa25
157921c466
hex4d7e9829

1300142121 has 8 divisors (see below), whose sum is σ = 1741739424. Its totient is φ = 862653120.

The previous prime is 1300142111. The next prime is 1300142143. The reversal of 1300142121 is 1212410031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1300142121 - 213 = 1300133929 is a prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1300142121.

It is not an unprimeable number, because it can be changed into a prime (1300142111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1026336 + ... + 1027601.

It is an arithmetic number, because the mean of its divisors is an integer number (217717428).

Almost surely, 21300142121 is an apocalyptic number.

It is an amenable number.

1300142121 is a deficient number, since it is larger than the sum of its proper divisors (441597303).

1300142121 is a wasteful number, since it uses less digits than its factorization.

1300142121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2054151.

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 1300142121 is about 36057.4835644419. The cubic root of 1300142121 is about 1091.4326533677.

Adding to 1300142121 its reverse (1212410031), we get a palindrome (2512552152).

The spelling of 1300142121 in words is "one billion, three hundred million, one hundred forty-two thousand, one hundred twenty-one".

Divisors: 1 3 211 633 2053937 6161811 433380707 1300142121