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130014321313 is a prime number
BaseRepresentation
bin111100100010101110…
…1010001101010100001
3110102120220212211202211
41321011131101222201
54112232131240223
6135421110042121
712251606332312
oct1710535215241
9412526784684
10130014321313
1150158770a28
1221245649341
13c34cb4a296
146415356609
1535ae241d0d
hex1e45751aa1

130014321313 has 2 divisors, whose sum is σ = 130014321314. Its totient is φ = 130014321312.

The previous prime is 130014321277. The next prime is 130014321391. The reversal of 130014321313 is 313123410031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 78373122304 + 51641199009 = 279952^2 + 227247^2 .

It is an emirp because it is prime and its reverse (313123410031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130014321313 is a prime.

It is not a weakly prime, because it can be changed into another prime (130014381313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65007160656 + 65007160657.

It is an arithmetic number, because the mean of its divisors is an integer number (65007160657).

Almost surely, 2130014321313 is an apocalyptic number.

It is an amenable number.

130014321313 is a deficient number, since it is larger than the sum of its proper divisors (1).

130014321313 is an equidigital number, since it uses as much as digits as its factorization.

130014321313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 130014321313 its reverse (313123410031), we get a palindrome (443137731344).

The spelling of 130014321313 in words is "one hundred thirty billion, fourteen million, three hundred twenty-one thousand, three hundred thirteen".