Base | Representation |
---|---|
bin | 10010111010110111101… |
… | …110010000101010100001 |
3 | 11121021221120002022222121 |
4 | 102322313232100222201 |
5 | 132300213043341201 |
6 | 2433141510104241 |
7 | 162635144512342 |
oct | 22726756205241 |
9 | 4537846068877 |
10 | 1300162480801 |
11 | 461439909448 |
12 | 18bb9194b081 |
13 | 957b2976122 |
14 | 46cdcda20c9 |
15 | 23c4831c9a1 |
hex | 12eb7b90aa1 |
1300162480801 has 2 divisors, whose sum is σ = 1300162480802. Its totient is φ = 1300162480800.
The previous prime is 1300162480777. The next prime is 1300162480811. The reversal of 1300162480801 is 1080842610031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1297093210000 + 3069270801 = 1138900^2 + 55401^2 .
It is an emirp because it is prime and its reverse (1080842610031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1300162480801 - 229 = 1299625609889 is a prime.
It is a super-2 number, since 2×13001624808012 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1300162480811) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650081240400 + 650081240401.
It is an arithmetic number, because the mean of its divisors is an integer number (650081240401).
Almost surely, 21300162480801 is an apocalyptic number.
It is an amenable number.
1300162480801 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300162480801 is an equidigital number, since it uses as much as digits as its factorization.
1300162480801 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 34.
The spelling of 1300162480801 in words is "one trillion, three hundred billion, one hundred sixty-two million, four hundred eighty thousand, eight hundred one".
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