Base | Representation |
---|---|
bin | 1011110100110100010000… |
… | …0110111111000001100011 |
3 | 1201000222110100012101101212 |
4 | 2331031010012333001203 |
5 | 3201011103210433231 |
6 | 43353012413420335 |
7 | 2511235616222663 |
oct | 275150406770143 |
9 | 51028410171355 |
10 | 13002008686691 |
11 | 4163136a3a842 |
12 | 155ba6249a6ab |
13 | 734112b8461b |
14 | 32d42cb021a3 |
15 | 17832abb342b |
hex | bd3441bf063 |
13002008686691 has 2 divisors, whose sum is σ = 13002008686692. Its totient is φ = 13002008686690.
The previous prime is 13002008686603. The next prime is 13002008686703. The reversal of 13002008686691 is 19668680020031.
13002008686691 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13002008686691 - 218 = 13002008424547 is a prime.
It is not a weakly prime, because it can be changed into another prime (13002008683691) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501004343345 + 6501004343346.
It is an arithmetic number, because the mean of its divisors is an integer number (6501004343346).
Almost surely, 213002008686691 is an apocalyptic number.
13002008686691 is a deficient number, since it is larger than the sum of its proper divisors (1).
13002008686691 is an equidigital number, since it uses as much as digits as its factorization.
13002008686691 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 746496, while the sum is 50.
The spelling of 13002008686691 in words is "thirteen trillion, two billion, eight million, six hundred eighty-six thousand, six hundred ninety-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •