130020212120131 has 4 divisors (see below), whose sum is σ = 130024475527752. Its totient is φ = 130015948712512.

The previous prime is 130020212120093. The next prime is 130020212120251. The reversal of 130020212120131 is 131021212020031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130020212120131 - 2²¹ = 130020210022979 is a prime.

It is a super-2 number, since 2×130020212120131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130020212120099 and 130020212120108.

It is not an unprimeable number, because it can be changed into a prime (130020212120531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2131658065 + ... + 2131719058.

It is an arithmetic number, because the mean of its divisors is an integer number (32506118881938).

Almost surely, 2^{130020212120131} is an apocalyptic number.

130020212120131 is a deficient number, since it is larger than the sum of its proper divisors (4263407621).

130020212120131 is an equidigital number, since it uses as much as digits as its factorization.

130020212120131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4263407620.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 130020212120131 its reverse (131021212020031), we get a palindrome (261041424140162).

The spelling of 130020212120131 in words is "one hundred thirty trillion, twenty billion, two hundred twelve million, one hundred twenty thousand, one hundred thirty-one".