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1300211313241 is a prime number
BaseRepresentation
bin10010111010111010101…
…000100010101001011001
311121022001221222021111111
4102322322220202221121
5132300313044010431
62433150412500321
7162636306545101
oct22727250425131
94538057867444
101300211313241
11461464431a35
1218bba617a6a1
13957bcb12c69
1446d05674201
1523c4c7667b1
hex12ebaa22a59

1300211313241 has 2 divisors, whose sum is σ = 1300211313242. Its totient is φ = 1300211313240.

The previous prime is 1300211313223. The next prime is 1300211313371. The reversal of 1300211313241 is 1423131120031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 812314651225 + 487896662016 = 901285^2 + 698496^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300211313241 - 25 = 1300211313209 is a prime.

It is not a weakly prime, because it can be changed into another prime (1300211313041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650105656620 + 650105656621.

It is an arithmetic number, because the mean of its divisors is an integer number (650105656621).

Almost surely, 21300211313241 is an apocalyptic number.

It is an amenable number.

1300211313241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300211313241 is an equidigital number, since it uses as much as digits as its factorization.

1300211313241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 1300211313241 its reverse (1423131120031), we get a palindrome (2723342433272).

The spelling of 1300211313241 in words is "one trillion, three hundred billion, two hundred eleven million, three hundred thirteen thousand, two hundred forty-one".