Base | Representation |
---|---|
bin | 11101100100000011100111… |
… | …011101000010000011110001 |
3 | 122001100220021022201121221001 |
4 | 131210003213131002003301 |
5 | 114020231240040211032 |
6 | 1140310514534202001 |
7 | 36246500613313321 |
oct | 3544034735020361 |
9 | 561326238647831 |
10 | 130021133132017 |
11 | 38479720011096 |
12 | 126bab724b3301 |
13 | 5771c2b94122a |
14 | 24170b0b69281 |
15 | 1007234a423e7 |
hex | 7640e77420f1 |
130021133132017 has 2 divisors, whose sum is σ = 130021133132018. Its totient is φ = 130021133132016.
The previous prime is 130021133131993. The next prime is 130021133132027. The reversal of 130021133132017 is 710231331120031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 116089397721441 + 13931735410576 = 10774479^2 + 3732524^2 .
It is a cyclic number.
It is not a de Polignac number, because 130021133132017 - 223 = 130021124743409 is a prime.
It is not a weakly prime, because it can be changed into another prime (130021133132027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65010566566008 + 65010566566009.
It is an arithmetic number, because the mean of its divisors is an integer number (65010566566009).
Almost surely, 2130021133132017 is an apocalyptic number.
It is an amenable number.
130021133132017 is a deficient number, since it is larger than the sum of its proper divisors (1).
130021133132017 is an equidigital number, since it uses as much as digits as its factorization.
130021133132017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2268, while the sum is 28.
Adding to 130021133132017 its reverse (710231331120031), we get a palindrome (840252464252048).
The spelling of 130021133132017 in words is "one hundred thirty trillion, twenty-one billion, one hundred thirty-three million, one hundred thirty-two thousand, seventeen".
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