Base | Representation |
---|---|
bin | 111100100010111100… |
… | …0011111000111100111 |
3 | 110102121102022020101221 |
4 | 1321011320133013213 |
5 | 4112240443014221 |
6 | 135421523001211 |
7 | 12252024061240 |
oct | 1710570370747 |
9 | 412542266357 |
10 | 130021454311 |
11 | 501617a3071 |
12 | 21247b09207 |
13 | c351476ba8 |
14 | 6416291cc7 |
15 | 35aeba0541 |
hex | 1e45e1f1e7 |
130021454311 has 32 divisors (see below), whose sum is σ = 155296310400. Its totient is φ = 106562926080.
The previous prime is 130021454281. The next prime is 130021454359. The reversal of 130021454311 is 113454120031.
It is a cyclic number.
It is not a de Polignac number, because 130021454311 - 25 = 130021454279 is a prime.
It is a super-2 number, since 2×1300214543112 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130021454611) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2440425 + ... + 2493133.
It is an arithmetic number, because the mean of its divisors is an integer number (4853009700).
Almost surely, 2130021454311 is an apocalyptic number.
130021454311 is a deficient number, since it is larger than the sum of its proper divisors (25274856089).
130021454311 is a wasteful number, since it uses less digits than its factorization.
130021454311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52939.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 130021454311 its reverse (113454120031), we get a palindrome (243475574342).
The spelling of 130021454311 in words is "one hundred thirty billion, twenty-one million, four hundred fifty-four thousand, three hundred eleven".
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