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130021454311 = 7536110952709
BaseRepresentation
bin111100100010111100…
…0011111000111100111
3110102121102022020101221
41321011320133013213
54112240443014221
6135421523001211
712252024061240
oct1710570370747
9412542266357
10130021454311
11501617a3071
1221247b09207
13c351476ba8
146416291cc7
1535aeba0541
hex1e45e1f1e7

130021454311 has 32 divisors (see below), whose sum is σ = 155296310400. Its totient is φ = 106562926080.

The previous prime is 130021454281. The next prime is 130021454359. The reversal of 130021454311 is 113454120031.

It is a cyclic number.

It is not a de Polignac number, because 130021454311 - 25 = 130021454279 is a prime.

It is a super-2 number, since 2×1300214543112 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130021454611) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2440425 + ... + 2493133.

It is an arithmetic number, because the mean of its divisors is an integer number (4853009700).

Almost surely, 2130021454311 is an apocalyptic number.

130021454311 is a deficient number, since it is larger than the sum of its proper divisors (25274856089).

130021454311 is a wasteful number, since it uses less digits than its factorization.

130021454311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 52939.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 130021454311 its reverse (113454120031), we get a palindrome (243475574342).

The spelling of 130021454311 in words is "one hundred thirty billion, twenty-one million, four hundred fifty-four thousand, three hundred eleven".

Divisors: 1 7 53 61 109 371 427 763 3233 5777 6649 22631 40439 46543 52709 352397 368963 2466779 2793577 3215249 5745281 19555039 22506743 40216967 170408197 304499893 350462141 1192857379 2131499251 2453234987 18574493473 130021454311