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130022100203131 is a prime number
BaseRepresentation
bin11101100100000100100001…
…000110000111011001111011
3122001100222202201102221002201
4131210010201012013121323
5114020240230123000011
61140311154522011031
736246533565266533
oct3544044106073173
9561328681387081
10130022100203131
113847a076993a14
12126bb1a2346a77
1357720540bc266
1424171633844c3
15100728e8bbcc1
hex76412118767b

130022100203131 has 2 divisors, whose sum is σ = 130022100203132. Its totient is φ = 130022100203130.

The previous prime is 130022100203077. The next prime is 130022100203201. The reversal of 130022100203131 is 131302001220031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 130022100203131 - 213 = 130022100194939 is a prime.

It is a super-2 number, since 2×1300221002031312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130022100203099 and 130022100203108.

It is not a weakly prime, because it can be changed into another prime (130022100203531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65011050101565 + 65011050101566.

It is an arithmetic number, because the mean of its divisors is an integer number (65011050101566).

Almost surely, 2130022100203131 is an apocalyptic number.

130022100203131 is a deficient number, since it is larger than the sum of its proper divisors (1).

130022100203131 is an equidigital number, since it uses as much as digits as its factorization.

130022100203131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 130022100203131 its reverse (131302001220031), we get a palindrome (261324101423162).

The spelling of 130022100203131 in words is "one hundred thirty trillion, twenty-two billion, one hundred million, two hundred three thousand, one hundred thirty-one".