Base | Representation |
---|---|
bin | 11101100100000100100010… |
… | …011001000000001111110011 |
3 | 122001100222211020022212011212 |
4 | 131210010202121000033303 |
5 | 114020240301203304023 |
6 | 1140311201015430335 |
7 | 36246534251055365 |
oct | 3544044231001763 |
9 | 561328736285155 |
10 | 130022121931763 |
11 | 3847a088184a66 |
12 | 126bb1a96853ab |
13 | 5772058759439 |
14 | 24171661dcd35 |
15 | 100729175ee78 |
hex | 7641226403f3 |
130022121931763 has 2 divisors, whose sum is σ = 130022121931764. Its totient is φ = 130022121931762.
The previous prime is 130022121931687. The next prime is 130022121931861. The reversal of 130022121931763 is 367139121220031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130022121931763 - 212 = 130022121927667 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 130022121931763.
It is not a weakly prime, because it can be changed into another prime (130022121931463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65011060965881 + 65011060965882.
It is an arithmetic number, because the mean of its divisors is an integer number (65011060965882).
Almost surely, 2130022121931763 is an apocalyptic number.
130022121931763 is a deficient number, since it is larger than the sum of its proper divisors (1).
130022121931763 is an equidigital number, since it uses as much as digits as its factorization.
130022121931763 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81648, while the sum is 41.
The spelling of 130022121931763 in words is "one hundred thirty trillion, twenty-two billion, one hundred twenty-one million, nine hundred thirty-one thousand, seven hundred sixty-three".
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