Base | Representation |
---|---|
bin | 11000001101111111… |
… | …00111000110010011 |
3 | 1020120011000020201101 |
4 | 30012333213012103 |
5 | 203112033143103 |
6 | 5550111045231 |
7 | 640131135265 |
oct | 140677470623 |
9 | 36504006641 |
10 | 13002240403 |
11 | 5572475729 |
12 | 262a510817 |
13 | 12c29a7699 |
14 | 8b4b8db35 |
15 | 511745a1d |
hex | 306fe7193 |
13002240403 has 2 divisors, whose sum is σ = 13002240404. Its totient is φ = 13002240402.
The previous prime is 13002240397. The next prime is 13002240413. The reversal of 13002240403 is 30404220031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13002240403 - 225 = 12968685971 is a prime.
It is not a weakly prime, because it can be changed into another prime (13002240413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501120201 + 6501120202.
It is an arithmetic number, because the mean of its divisors is an integer number (6501120202).
Almost surely, 213002240403 is an apocalyptic number.
13002240403 is a deficient number, since it is larger than the sum of its proper divisors (1).
13002240403 is an equidigital number, since it uses as much as digits as its factorization.
13002240403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 19.
Adding to 13002240403 its reverse (30404220031), we get a palindrome (43406460434).
The spelling of 13002240403 in words is "thirteen billion, two million, two hundred forty thousand, four hundred three".
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