Base | Representation |
---|---|
bin | 1011110100110101010110… |
… | …1010100000001011100011 |
3 | 1201001000012212101201201101 |
4 | 2331031111222200023203 |
5 | 3201012204110211321 |
6 | 43353101534215231 |
7 | 2511246123513100 |
oct | 275152552401343 |
9 | 51030185351641 |
10 | 13002303210211 |
11 | 4163278213707 |
12 | 155bb25054517 |
13 | 73415bbb57b3 |
14 | 32d459c8baa7 |
15 | 17834698e791 |
hex | bd355aa02e3 |
13002303210211 has 12 divisors (see below), whose sum is σ = 15126656424960. Its totient is φ = 11143705280400.
The previous prime is 13002303210209. The next prime is 13002303210229. The reversal of 13002303210211 is 11201230320031.
13002303210211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13002303210211 - 21 = 13002303210209 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13002303220211) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 12915171 + ... + 13885468.
It is an arithmetic number, because the mean of its divisors is an integer number (1260554702080).
Almost surely, 213002303210211 is an apocalyptic number.
13002303210211 is a deficient number, since it is larger than the sum of its proper divisors (2124353214749).
13002303210211 is an equidigital number, since it uses as much as digits as its factorization.
13002303210211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26810554 (or 26810547 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 13002303210211 its reverse (11201230320031), we get a palindrome (24203533530242).
The spelling of 13002303210211 in words is "thirteen trillion, two billion, three hundred three million, two hundred ten thousand, two hundred eleven".
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