Base | Representation |
---|---|
bin | 111100100011000001… |
… | …0011001110100010001 |
3 | 110102121121012022112221 |
4 | 1321012002121310101 |
5 | 4112242124212113 |
6 | 135422054421041 |
7 | 12252055136506 |
oct | 1710602316421 |
9 | 412547168487 |
10 | 130024054033 |
11 | 501632092a5 |
12 | 21248961781 |
13 | c351b772a3 |
14 | 641676b4ad |
15 | 35b001598d |
hex | 1e46099d11 |
130024054033 has 2 divisors, whose sum is σ = 130024054034. Its totient is φ = 130024054032.
The previous prime is 130024053967. The next prime is 130024054087. The reversal of 130024054033 is 330450420031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 127672579969 + 2351474064 = 357313^2 + 48492^2 .
It is a cyclic number.
It is not a de Polignac number, because 130024054033 - 217 = 130023922961 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130024053989 and 130024054007.
It is not a weakly prime, because it can be changed into another prime (130024054133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65012027016 + 65012027017.
It is an arithmetic number, because the mean of its divisors is an integer number (65012027017).
Almost surely, 2130024054033 is an apocalyptic number.
It is an amenable number.
130024054033 is a deficient number, since it is larger than the sum of its proper divisors (1).
130024054033 is an equidigital number, since it uses as much as digits as its factorization.
130024054033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 25.
Adding to 130024054033 its reverse (330450420031), we get a palindrome (460474474064).
The spelling of 130024054033 in words is "one hundred thirty billion, twenty-four million, fifty-four thousand, thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •