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13002441034 = 2114491316303
BaseRepresentation
bin11000001110000000…
…11000000101001010
31020120011101102221011
430013000120011022
5203112111103114
65550115234134
7640132632232
oct140700300512
936504342834
1013002441034
1155725a2440
12262a5a894a
1312c2a47abb
148b4c02cc2
155117851c4
hex30701814a

13002441034 has 16 divisors (see below), whose sum is σ = 21324124800. Its totient is φ = 5897032960.

The previous prime is 13002440959. The next prime is 13002441037. The reversal of 13002441034 is 43014420031.

It is a super-3 number, since 3×130024410343 (a number of 31 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (22).

It is a junction number, because it is equal to n+sod(n) for n = 13002440996 and 13002441014.

It is not an unprimeable number, because it can be changed into a prime (13002441037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 648274 + ... + 668029.

It is an arithmetic number, because the mean of its divisors is an integer number (1332757800).

Almost surely, 213002441034 is an apocalyptic number.

13002441034 is a deficient number, since it is larger than the sum of its proper divisors (8321683766).

13002441034 is a wasteful number, since it uses less digits than its factorization.

13002441034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1316765.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 13002441034 its reverse (43014420031), we get a palindrome (56016861065).

The spelling of 13002441034 in words is "thirteen billion, two million, four hundred forty-one thousand, thirty-four".

Divisors: 1 2 11 22 449 898 4939 9878 1316303 2632606 14479333 28958666 591020047 1182040094 6501220517 13002441034