Base | Representation |
---|---|
bin | 111100100011000011… |
… | …1010001110100110011 |
3 | 110102121200121020121202 |
4 | 1321012013101310303 |
5 | 4112242441111034 |
6 | 135422142041415 |
7 | 12252102041432 |
oct | 1710607216463 |
9 | 412550536552 |
10 | 130025332019 |
11 | 50163a01490 |
12 | 2124927926b |
13 | c352203bab |
14 | 64169c1119 |
15 | 35b01b947e |
hex | 1e461d1d33 |
130025332019 has 16 divisors (see below), whose sum is σ = 146437057536. Its totient is φ = 114379624800.
The previous prime is 130025332009. The next prime is 130025332039. The reversal of 130025332019 is 910233520031.
It is a cyclic number.
It is not a de Polignac number, because 130025332019 - 28 = 130025331763 is a prime.
It is a super-2 number, since 2×1300253320192 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 130025331982 and 130025332000.
It is not an unprimeable number, because it can be changed into a prime (130025332009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5043149 + ... + 5068865.
It is an arithmetic number, because the mean of its divisors is an integer number (9152316096).
Almost surely, 2130025332019 is an apocalyptic number.
130025332019 is a deficient number, since it is larger than the sum of its proper divisors (16411725517).
130025332019 is a wasteful number, since it uses less digits than its factorization.
130025332019 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40586.
The product of its (nonzero) digits is 4860, while the sum is 29.
The spelling of 130025332019 in words is "one hundred thirty billion, twenty-five million, three hundred thirty-two thousand, nineteen".
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