130025431451 has 4 divisors (see below), whose sum is σ = 130113110232. Its totient is φ = 129937752672.

The previous prime is 130025431441. The next prime is 130025431457. The reversal of 130025431451 is 154134520031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130025431451 is a prime.

It is a super-2 number, since 2×130025431451² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130025431457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43837166 + ... + 43840131.

It is an arithmetic number, because the mean of its divisors is an integer number (32528277558).

Almost surely, 2^130025431451 is an apocalyptic number.

130025431451 is a deficient number, since it is larger than the sum of its proper divisors (87678781).

130025431451 is an equidigital number, since it uses as much as digits as its factorization.

130025431451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 87678780.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 130025431451 its reverse (154134520031), we get a palindrome (284159951482).

The spelling of 130025431451 in words is "one hundred thirty billion, twenty-five million, four hundred thirty-one thousand, four hundred fifty-one".