1300303100113 has 4 divisors (see below), whose sum is σ = 1315969402608. Its totient is φ = 1284636797620.

The previous prime is 1300303100099. The next prime is 1300303100171. The reversal of 1300303100113 is 3110013030031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1300303100113 - 2⁵ = 1300303100081 is a prime.

It is a super-2 number, since 2×1300303100113² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1300303109113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7833151123 + ... + 7833151288.

It is an arithmetic number, because the mean of its divisors is an integer number (328992350652).

Almost surely, 2^{1300303100113} is an apocalyptic number.

It is an amenable number.

1300303100113 is a deficient number, since it is larger than the sum of its proper divisors (15666302495).

1300303100113 is an equidigital number, since it uses as much as digits as its factorization.

1300303100113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15666302494.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 1300303100113 its reverse (3110013030031), we get a palindrome (4410316130144).

The spelling of 1300303100113 in words is "one trillion, three hundred billion, three hundred three million, one hundred thousand, one hundred thirteen".