Base | Representation |
---|---|
bin | 1011110100111000010111… |
… | …0000101010101001101010 |
3 | 1201001002022002202121202210 |
4 | 2331032011300222221222 |
5 | 3201020332143213310 |
6 | 43353314001305550 |
7 | 2511305122316523 |
oct | 275160560525152 |
9 | 51032262677683 |
10 | 13003110132330 |
11 | 416365175219a |
12 | 156010b3352b6 |
13 | 73425a1202c6 |
14 | 32d4d50d984a |
15 | 178392732820 |
hex | bd385c2aa6a |
13003110132330 has 256 divisors, whose sum is σ = 32605064110080. Its totient is φ = 3316737715200.
The previous prime is 13003110132301. The next prime is 13003110132347. The reversal of 13003110132330 is 3323101130031.
13003110132330 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×130031101323302 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13003110132297 and 13003110132306.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 9979362459 + ... + 9979363761.
It is an arithmetic number, because the mean of its divisors is an integer number (127363531680).
Almost surely, 213003110132330 is an apocalyptic number.
13003110132330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 13003110132330, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16302532055040).
13003110132330 is an abundant number, since it is smaller than the sum of its proper divisors (19601953977750).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13003110132330 is a wasteful number, since it uses less digits than its factorization.
13003110132330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2357.
The product of its (nonzero) digits is 486, while the sum is 21.
Adding to 13003110132330 its reverse (3323101130031), we get a palindrome (16326211262361).
The spelling of 13003110132330 in words is "thirteen trillion, three billion, one hundred ten million, one hundred thirty-two thousand, three hundred thirty".
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