13003111123 has 2 divisors, whose sum is σ = 13003111124. Its totient is φ = 13003111122.

The previous prime is 13003111117. The next prime is 13003111151. The reversal of 13003111123 is 32111130031.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13003111123 is a prime.

It is a super-2 number, since 2×13003111123² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13003111097 and 13003111106.

It is not a weakly prime, because it can be changed into another prime (13003111153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501555561 + 6501555562.

It is an arithmetic number, because the mean of its divisors is an integer number (6501555562).

Almost surely, 2^13003111123 is an apocalyptic number.

13003111123 is a deficient number, since it is larger than the sum of its proper divisors (1).

13003111123 is an equidigital number, since it uses as much as digits as its factorization.

13003111123 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 13003111123 its reverse (32111130031), we get a palindrome (45114241154).

The spelling of 13003111123 in words is "thirteen billion, three million, one hundred eleven thousand, one hundred twenty-three".