Base | Representation |
---|---|
bin | 11101100100001100111111… |
… | …100110110000010001011010 |
3 | 122001101212021001002122011022 |
4 | 131210030333212300101122 |
5 | 114020412400203311302 |
6 | 1140315302021202442 |
7 | 36250305255340313 |
oct | 3544147746602132 |
9 | 561355231078138 |
10 | 130031202010202 |
11 | 38482a176a0319 |
12 | 12700b02560422 |
13 | 5772b7499670c |
14 | 24177880db60a |
15 | 10076239a88a2 |
hex | 76433f9b045a |
130031202010202 has 16 divisors (see below), whose sum is σ = 199225261953792. Its totient is φ = 63623177566800.
The previous prime is 130031202010189. The next prime is 130031202010261. The reversal of 130031202010202 is 202010202130031.
130031202010202 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×1300312020102022 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 98392049 + ... + 99704852.
It is an arithmetic number, because the mean of its divisors is an integer number (12451578872112).
Almost surely, 2130031202010202 is an apocalyptic number.
130031202010202 is a deficient number, since it is larger than the sum of its proper divisors (69194059943590).
130031202010202 is a wasteful number, since it uses less digits than its factorization.
130031202010202 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 198103933.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 130031202010202 its reverse (202010202130031), we get a palindrome (332041404140233).
It can be divided in two parts, 130031 and 202010202, that multiplied together give a palindrome (26267588576262).
The spelling of 130031202010202 in words is "one hundred thirty trillion, thirty-one billion, two hundred two million, ten thousand, two hundred two".
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