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130032220031122 = 265016110015561
BaseRepresentation
bin11101100100001101111100…
…010010001100100010010010
3122001101221212222200110022211
4131210031330102030202102
5114020421441311443442
61140315551025022334
736250342426355323
oct3544157422144222
9561357788613284
10130032220031122
113848339a302522
12127011474849aa
135772ca7873266
1424178433ba44a
151007683049617
hex76437c48c892

130032220031122 has 4 divisors (see below), whose sum is σ = 195048330046686. Its totient is φ = 65016110015560.

The previous prime is 130032220031069. The next prime is 130032220031167. The reversal of 130032220031122 is 221130022230031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 100116253767721 + 29915966263401 = 10005811^2 + 5469549^2 .

It is a junction number, because it is equal to n+sod(n) for n = 130032220031093 and 130032220031102.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32508055007779 + ... + 32508055007782.

Almost surely, 2130032220031122 is an apocalyptic number.

130032220031122 is a deficient number, since it is larger than the sum of its proper divisors (65016110015564).

130032220031122 is an equidigital number, since it uses as much as digits as its factorization.

130032220031122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65016110015563.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 130032220031122 its reverse (221130022230031), we get a palindrome (351162242261153).

The spelling of 130032220031122 in words is "one hundred thirty trillion, thirty-two billion, two hundred twenty million, thirty-one thousand, one hundred twenty-two".

Divisors: 1 2 65016110015561 130032220031122