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13003230003403 = 13219843474643
BaseRepresentation
bin1011110100111000110011…
…1001111100000011001011
31201001002121110022200222011
42331032030321330003023
53201021103340102103
643353333522440351
72511311106233053
oct275161471740313
951032543280864
1013003230003403
1141637033860a2
1215601435030b7
13734278c00633
1432d506dc0563
1517839d00ed6d
hexbd38ce7c0cb

13003230003403 has 4 divisors (see below), whose sum is σ = 13013073479368. Its totient is φ = 12993386527440.

The previous prime is 13003230003397. The next prime is 13003230003509. The reversal of 13003230003403 is 30430003230031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13003230003403 - 25 = 13003230003371 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13003230003103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4921736001 + ... + 4921738642.

It is an arithmetic number, because the mean of its divisors is an integer number (3253268369842).

Almost surely, 213003230003403 is an apocalyptic number.

13003230003403 is a deficient number, since it is larger than the sum of its proper divisors (9843475965).

13003230003403 is an equidigital number, since it uses as much as digits as its factorization.

13003230003403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9843475964.

The product of its (nonzero) digits is 1944, while the sum is 22.

Adding to 13003230003403 its reverse (30430003230031), we get a palindrome (43433233233434).

The spelling of 13003230003403 in words is "thirteen trillion, three billion, two hundred thirty million, three thousand, four hundred three".

Divisors: 1 1321 9843474643 13003230003403