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130033130010089 is a prime number
BaseRepresentation
bin11101100100001110110010…
…100001011111010111101001
3122001102001020101222011210112
4131210032302201133113221
5114020430322240310324
61140320221213024105
736250404116145245
oct3544166241372751
9561361211864715
10130033130010089
1138483816a30159
1212701360185035
1357730c1251a57
1424178cc1b3425
1510076d7d97c0e
hex7643b285f5e9

130033130010089 has 2 divisors, whose sum is σ = 130033130010090. Its totient is φ = 130033130010088.

The previous prime is 130033130010071. The next prime is 130033130010103. The reversal of 130033130010089 is 980010031330031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 125030034712489 + 5003095297600 = 11181683^2 + 2236760^2 .

It is a cyclic number.

It is not a de Polignac number, because 130033130010089 - 212 = 130033130005993 is a prime.

It is a super-2 number, since 2×1300331300100892 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130033130010059) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65016565005044 + 65016565005045.

It is an arithmetic number, because the mean of its divisors is an integer number (65016565005045).

Almost surely, 2130033130010089 is an apocalyptic number.

It is an amenable number.

130033130010089 is a deficient number, since it is larger than the sum of its proper divisors (1).

130033130010089 is an equidigital number, since it uses as much as digits as its factorization.

130033130010089 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5832, while the sum is 32.

The spelling of 130033130010089 in words is "one hundred thirty trillion, thirty-three billion, one hundred thirty million, ten thousand, eighty-nine".