Base | Representation |
---|---|
bin | 11101100100001110110010… |
… | …100001011111010111101001 |
3 | 122001102001020101222011210112 |
4 | 131210032302201133113221 |
5 | 114020430322240310324 |
6 | 1140320221213024105 |
7 | 36250404116145245 |
oct | 3544166241372751 |
9 | 561361211864715 |
10 | 130033130010089 |
11 | 38483816a30159 |
12 | 12701360185035 |
13 | 57730c1251a57 |
14 | 24178cc1b3425 |
15 | 10076d7d97c0e |
hex | 7643b285f5e9 |
130033130010089 has 2 divisors, whose sum is σ = 130033130010090. Its totient is φ = 130033130010088.
The previous prime is 130033130010071. The next prime is 130033130010103. The reversal of 130033130010089 is 980010031330031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 125030034712489 + 5003095297600 = 11181683^2 + 2236760^2 .
It is a cyclic number.
It is not a de Polignac number, because 130033130010089 - 212 = 130033130005993 is a prime.
It is a super-2 number, since 2×1300331300100892 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (130033130010059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65016565005044 + 65016565005045.
It is an arithmetic number, because the mean of its divisors is an integer number (65016565005045).
Almost surely, 2130033130010089 is an apocalyptic number.
It is an amenable number.
130033130010089 is a deficient number, since it is larger than the sum of its proper divisors (1).
130033130010089 is an equidigital number, since it uses as much as digits as its factorization.
130033130010089 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 32.
The spelling of 130033130010089 in words is "one hundred thirty trillion, thirty-three billion, one hundred thirty million, ten thousand, eighty-nine".
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