Base | Representation |
---|---|
bin | 11101100100001110110111… |
… | …011110000111110010100001 |
3 | 122001102001110012011011121002 |
4 | 131210032313132013302201 |
5 | 114020431010012410103 |
6 | 1140320233340041345 |
7 | 36250406144516552 |
oct | 3544166736076241 |
9 | 561361405134532 |
10 | 130033213013153 |
11 | 3848385987262a |
12 | 12701383b33255 |
13 | 57731054c3ca8 |
14 | 24178d921c329 |
15 | 10076e02e1488 |
hex | 7643b7787ca1 |
130033213013153 has 2 divisors, whose sum is σ = 130033213013154. Its totient is φ = 130033213013152.
The previous prime is 130033213013113. The next prime is 130033213013219. The reversal of 130033213013153 is 351310312330031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 91440392627809 + 38592820385344 = 9562447^2 + 6212312^2 .
It is a cyclic number.
It is not a de Polignac number, because 130033213013153 - 212 = 130033213009057 is a prime.
It is not a weakly prime, because it can be changed into another prime (130033213013113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65016606506576 + 65016606506577.
It is an arithmetic number, because the mean of its divisors is an integer number (65016606506577).
Almost surely, 2130033213013153 is an apocalyptic number.
It is an amenable number.
130033213013153 is a deficient number, since it is larger than the sum of its proper divisors (1).
130033213013153 is an equidigital number, since it uses as much as digits as its factorization.
130033213013153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7290, while the sum is 29.
Adding to 130033213013153 its reverse (351310312330031), we get a palindrome (481343525343184).
The spelling of 130033213013153 in words is "one hundred thirty trillion, thirty-three billion, two hundred thirteen million, thirteen thousand, one hundred fifty-three".
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