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130033321311217 is a prime number
BaseRepresentation
bin11101100100001110111101…
…111011001111101111110001
3122001102001201201221021121111
4131210032331323033233301
5114020431220223424332
61140320252205153321
736250411631162422
oct3544167573175761
9561361651837544
10130033321311217
1138483904a11565
12127013b425b841
135773121a8179c
14241790976d649
1510076e9a84947
hex7643bdecfbf1

130033321311217 has 2 divisors, whose sum is σ = 130033321311218. Its totient is φ = 130033321311216.

The previous prime is 130033321311197. The next prime is 130033321311227. The reversal of 130033321311217 is 712113123330031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109985055365376 + 20048265945841 = 10487376^2 + 4477529^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130033321311217 is a prime.

It is not a weakly prime, because it can be changed into another prime (130033321311227) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65016660655608 + 65016660655609.

It is an arithmetic number, because the mean of its divisors is an integer number (65016660655609).

Almost surely, 2130033321311217 is an apocalyptic number.

It is an amenable number.

130033321311217 is a deficient number, since it is larger than the sum of its proper divisors (1).

130033321311217 is an equidigital number, since it uses as much as digits as its factorization.

130033321311217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6804, while the sum is 31.

Adding to 130033321311217 its reverse (712113123330031), we get a palindrome (842146444641248).

The spelling of 130033321311217 in words is "one hundred thirty trillion, thirty-three billion, three hundred twenty-one million, three hundred eleven thousand, two hundred seventeen".