Base | Representation |
---|---|
bin | 10010111011000010010… |
… | …011011111010000001100 |
3 | 11121022101221010212001211 |
4 | 102323002103133100030 |
5 | 132301044020341134 |
6 | 2433211251144204 |
7 | 162642431506213 |
oct | 22730223372014 |
9 | 4538357125054 |
10 | 1300340012044 |
11 | 461520045287 |
12 | 1900212a5064 |
13 | 958106943b8 |
14 | 46d187b607a |
15 | 23c58bd9764 |
hex | 12ec24df40c |
1300340012044 has 12 divisors (see below), whose sum is σ = 2275607936224. Its totient is φ = 650166315984.
The previous prime is 1300340012017. The next prime is 1300340012053. The reversal of 1300340012044 is 4402100430031.
It is a super-3 number, since 3×13003400120443 (a number of 37 digits) contains 333 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34692 + ... + 1613035.
Almost surely, 21300340012044 is an apocalyptic number.
It is an amenable number.
1300340012044 is a deficient number, since it is larger than the sum of its proper divisors (975267924180).
1300340012044 is a wasteful number, since it uses less digits than its factorization.
1300340012044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1845024 (or 1845022 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 1300340012044 its reverse (4402100430031), we get a palindrome (5702440442075).
The spelling of 1300340012044 in words is "one trillion, three hundred billion, three hundred forty million, twelve thousand, forty-four".
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