Base | Representation |
---|---|
bin | 11101100100001111101011… |
… | …100010010111100000100011 |
3 | 122001102010201001212000000011 |
4 | 131210033223202113200203 |
5 | 114020434302123310342 |
6 | 1140320500142505351 |
7 | 36250436612423152 |
oct | 3544175342274043 |
9 | 561363631760004 |
10 | 130034086541347 |
11 | 3848416796425a |
12 | 12701588595257 |
13 | 577321447c591 |
14 | 241797d247599 |
15 | 1007741d3e717 |
hex | 7643eb897823 |
130034086541347 has 2 divisors, whose sum is σ = 130034086541348. Its totient is φ = 130034086541346.
The previous prime is 130034086541327. The next prime is 130034086541399. The reversal of 130034086541347 is 743145680430031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130034086541347 - 239 = 129484330727459 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 130034086541347.
It is not a weakly prime, because it can be changed into another prime (130034086541327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65017043270673 + 65017043270674.
It is an arithmetic number, because the mean of its divisors is an integer number (65017043270674).
Almost surely, 2130034086541347 is an apocalyptic number.
130034086541347 is a deficient number, since it is larger than the sum of its proper divisors (1).
130034086541347 is an equidigital number, since it uses as much as digits as its factorization.
130034086541347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2903040, while the sum is 49.
The spelling of 130034086541347 in words is "one hundred thirty trillion, thirty-four billion, eighty-six million, five hundred forty-one thousand, three hundred forty-seven".
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