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130034231202241 is a prime number
BaseRepresentation
bin11101100100001111110100…
…001010001101000111000001
3122001102011002011001112110001
4131210033310022031013001
5114020440101141432431
61140320522351240001
736250443320135062
oct3544176412150701
9561364064045401
10130034231202241
113848423158a113
1212701608b19001
13577323842c242
142417994542569
15100774e8b6e61
hex7643f428d1c1

130034231202241 has 2 divisors, whose sum is σ = 130034231202242. Its totient is φ = 130034231202240.

The previous prime is 130034231202233. The next prime is 130034231202263. The reversal of 130034231202241 is 142202132430031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 121523615250625 + 8510615951616 = 11023775^2 + 2917296^2 .

It is an emirp because it is prime and its reverse (142202132430031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130034231202241 - 23 = 130034231202233 is a prime.

It is not a weakly prime, because it can be changed into another prime (130034231208241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65017115601120 + 65017115601121.

It is an arithmetic number, because the mean of its divisors is an integer number (65017115601121).

Almost surely, 2130034231202241 is an apocalyptic number.

It is an amenable number.

130034231202241 is a deficient number, since it is larger than the sum of its proper divisors (1).

130034231202241 is an equidigital number, since it uses as much as digits as its factorization.

130034231202241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 130034231202241 its reverse (142202132430031), we get a palindrome (272236363632272).

The spelling of 130034231202241 in words is "one hundred thirty trillion, thirty-four billion, two hundred thirty-one million, two hundred two thousand, two hundred forty-one".