13004011404403 has 2 divisors, whose sum is σ = 13004011404404. Its totient is φ = 13004011404402.

The previous prime is 13004011404337. The next prime is 13004011404451. The reversal of 13004011404403 is 30440411040031.

It is a strong prime.

It is an emirp because it is prime and its reverse (30440411040031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13004011404403 is a prime.

It is not a weakly prime, because it can be changed into another prime (13004011414403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502005702201 + 6502005702202.

It is an arithmetic number, because the mean of its divisors is an integer number (6502005702202).

Almost surely, 2^{13004011404403} is an apocalyptic number.

13004011404403 is a deficient number, since it is larger than the sum of its proper divisors (1).

13004011404403 is an equidigital number, since it uses as much as digits as its factorization.

13004011404403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 13004011404403 its reverse (30440411040031), we get a palindrome (43444422444434).

The spelling of 13004011404403 in words is "thirteen trillion, four billion, eleven million, four hundred four thousand, four hundred three".