Base | Representation |
---|---|
bin | 1011110100111011101101… |
… | …1110101111110010010010 |
3 | 1201001011121220122222200002 |
4 | 2331032323132233302102 |
5 | 3201024203404420214 |
6 | 43353543234530002 |
7 | 2511336345104141 |
oct | 275167336576222 |
9 | 51034556588602 |
10 | 13004011404434 |
11 | 4163a74473276 |
12 | 1560321136902 |
13 | 734371a709cb |
14 | 32d57caa7758 |
15 | 1783e69111de |
hex | bd3bb7afc92 |
13004011404434 has 16 divisors (see below), whose sum is σ = 19750598969472. Its totient is φ = 6420554364048.
The previous prime is 13004011404403. The next prime is 13004011404451. The reversal of 13004011404434 is 43440411040031.
It is a super-2 number, since 2×130040114044342 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13004011404397 and 13004011404406.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18643829 + ... + 19328744.
It is an arithmetic number, because the mean of its divisors is an integer number (1234412435592).
Almost surely, 213004011404434 is an apocalyptic number.
13004011404434 is a deficient number, since it is larger than the sum of its proper divisors (6746587565038).
13004011404434 is a wasteful number, since it uses less digits than its factorization.
13004011404434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37974721.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 13004011404434 its reverse (43440411040031), we get a palindrome (56444422444465).
The spelling of 13004011404434 in words is "thirteen trillion, four billion, eleven million, four hundred four thousand, four hundred thirty-four".
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