Base | Representation |
---|---|
bin | 111100100011011111… |
… | …1101010110000101110 |
3 | 110102122201102020222202 |
4 | 1321012333222300232 |
5 | 4112310232123342 |
6 | 135423430541502 |
7 | 12252341506304 |
oct | 1710677526056 |
9 | 412581366882 |
10 | 130040114222 |
11 | 50171288587 |
12 | 21252207892 |
13 | c3552ab365 |
14 | 641894c274 |
15 | 35b1639332 |
hex | 1e46feac2e |
130040114222 has 32 divisors (see below), whose sum is σ = 206134917120. Its totient is φ = 61355849760.
The previous prime is 130040114219. The next prime is 130040114261. The reversal of 130040114222 is 222411040031.
It is a junction number, because it is equal to n+sod(n) for n = 130040114194 and 130040114203.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12226847 + ... + 12237477.
It is an arithmetic number, because the mean of its divisors is an integer number (6441716160).
Almost surely, 2130040114222 is an apocalyptic number.
130040114222 is a deficient number, since it is larger than the sum of its proper divisors (76094802898).
130040114222 is a wasteful number, since it uses less digits than its factorization.
130040114222 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11888.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 130040114222 its reverse (222411040031), we get a palindrome (352451154253).
The spelling of 130040114222 in words is "one hundred thirty billion, forty million, one hundred fourteen thousand, two hundred twenty-two".
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