Base | Representation |
---|---|
bin | 10010111011000110000… |
… | …000010101110011000001 |
3 | 11121022120020222022201010 |
4 | 102323012000111303001 |
5 | 132301210414221231 |
6 | 2433221350031133 |
7 | 162644114324652 |
oct | 22730600256301 |
9 | 4538506868633 |
10 | 1300402101441 |
11 | 4615520a2a33 |
12 | 19003a0484a9 |
13 | 958204c33a1 |
14 | 46d22b39529 |
15 | 23c5e3a1546 |
hex | 12ec6015cc1 |
1300402101441 has 16 divisors (see below), whose sum is σ = 1757747171840. Its totient is φ = 854997586560.
The previous prime is 1300402101421. The next prime is 1300402101451. The reversal of 1300402101441 is 1441012040031.
It is not a de Polignac number, because 1300402101441 - 223 = 1300393712833 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1300402101421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2954655 + ... + 3366123.
It is an arithmetic number, because the mean of its divisors is an integer number (109859198240).
Almost surely, 21300402101441 is an apocalyptic number.
It is an amenable number.
1300402101441 is a deficient number, since it is larger than the sum of its proper divisors (457345070399).
1300402101441 is a wasteful number, since it uses less digits than its factorization.
1300402101441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 425976.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 1300402101441 its reverse (1441012040031), we get a palindrome (2741414141472).
The spelling of 1300402101441 in words is "one trillion, three hundred billion, four hundred two million, one hundred one thousand, four hundred forty-one".
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