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1300402120242 = 23892435209963
BaseRepresentation
bin10010111011000110000…
…000011010011000110010
311121022120021000021111110
4102323012000122120302
5132301210420321432
62433221350254150
7162644114433531
oct22730600323062
94538507007443
101300402120242
11461552106075
1219003a057356
13958204cbb04
1446d22b42318
1523c5e3a6dcc
hex12ec601a632

1300402120242 has 16 divisors (see below), whose sum is σ = 2630026761120. Its totient is φ = 428596953312.

The previous prime is 1300402120219. The next prime is 1300402120247. The reversal of 1300402120242 is 2420212040031.

It is a super-2 number, since 2×13004021202422 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1300402120247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1217604448 + ... + 1217605515.

It is an arithmetic number, because the mean of its divisors is an integer number (164376672570).

Almost surely, 21300402120242 is an apocalyptic number.

1300402120242 is an abundant number, since it is smaller than the sum of its proper divisors (1329624640878).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300402120242 is a wasteful number, since it uses less digits than its factorization.

1300402120242 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2435210057.

The product of its (nonzero) digits is 768, while the sum is 21.

Adding to 1300402120242 its reverse (2420212040031), we get a palindrome (3720614160273).

The spelling of 1300402120242 in words is "one trillion, three hundred billion, four hundred two million, one hundred twenty thousand, two hundred forty-two".

Divisors: 1 2 3 6 89 178 267 534 2435209963 4870419926 7305629889 14611259778 216733686707 433467373414 650201060121 1300402120242