Search a number
-
+
1300402120331 = 8914611259779
BaseRepresentation
bin10010111011000110000…
…000011010011010001011
311121022120021000021121202
4102323012000122122023
5132301210420322311
62433221350254415
7162644114434016
oct22730600323213
94538507007552
101300402120331
11461552106146
1219003a05740b
13958204cbb72
1446d22b4237d
1523c5e3a6e3b
hex12ec601a68b

1300402120331 has 4 divisors (see below), whose sum is σ = 1315013380200. Its totient is φ = 1285790860464.

The previous prime is 1300402120313. The next prime is 1300402120373. The reversal of 1300402120331 is 1330212040031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1300402120331 - 210 = 1300402119307 is a prime.

It is a super-2 number, since 2×13004021203312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1300402120301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7305629801 + ... + 7305629978.

It is an arithmetic number, because the mean of its divisors is an integer number (328753345050).

Almost surely, 21300402120331 is an apocalyptic number.

1300402120331 is a deficient number, since it is larger than the sum of its proper divisors (14611259869).

1300402120331 is an equidigital number, since it uses as much as digits as its factorization.

1300402120331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14611259868.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 1300402120331 its reverse (1330212040031), we get a palindrome (2630614160362).

The spelling of 1300402120331 in words is "one trillion, three hundred billion, four hundred two million, one hundred twenty thousand, three hundred thirty-one".

Divisors: 1 89 14611259779 1300402120331