Base | Representation |
---|---|
bin | 111100100011100001… |
… | …1111011101111000011 |
3 | 110102122210112001201220 |
4 | 1321013003323233003 |
5 | 4112311023413243 |
6 | 135423510530123 |
7 | 12252354144132 |
oct | 1710703735703 |
9 | 412583461656 |
10 | 130041232323 |
11 | 50171981632 |
12 | 21252666943 |
13 | c3555b0262 |
14 | 6418b5d919 |
15 | 35b17aa783 |
hex | 1e470fbbc3 |
130041232323 has 4 divisors (see below), whose sum is σ = 173388309768. Its totient is φ = 86694154880.
The previous prime is 130041232319. The next prime is 130041232339. The reversal of 130041232323 is 323232140031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130041232323 - 22 = 130041232319 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130041232293 and 130041232302.
It is not an unprimeable number, because it can be changed into a prime (130041232393) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21673538718 + ... + 21673538723.
It is an arithmetic number, because the mean of its divisors is an integer number (43347077442).
Almost surely, 2130041232323 is an apocalyptic number.
130041232323 is a deficient number, since it is larger than the sum of its proper divisors (43347077445).
130041232323 is an equidigital number, since it uses as much as digits as its factorization.
130041232323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43347077444.
The product of its (nonzero) digits is 2592, while the sum is 24.
Adding to 130041232323 its reverse (323232140031), we get a palindrome (453273372354).
The spelling of 130041232323 in words is "one hundred thirty billion, forty-one million, two hundred thirty-two thousand, three hundred twenty-three".
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