Base | Representation |
---|---|
bin | 11000001110001110… |
… | …10010111101001011 |
3 | 1020120021210121021222 |
4 | 30013013102331023 |
5 | 203113042130201 |
6 | 5550222152255 |
7 | 640154226014 |
oct | 140707227513 |
9 | 36507717258 |
10 | 13004255051 |
11 | 5573621327 |
12 | 262b12268b |
13 | 12c3231698 |
14 | 8b515600b |
15 | 5119e291b |
hex | 3071d2f4b |
13004255051 has 8 divisors (see below), whose sum is σ = 13106918400. Its totient is φ = 12901994280.
The previous prime is 13004255029. The next prime is 13004255057. The reversal of 13004255051 is 15055240031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13004255051 is a prime.
It is a super-2 number, since 2×130042550512 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13004255051.
It is not an unprimeable number, because it can be changed into a prime (13004255057) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35621 + ... + 165158.
It is an arithmetic number, because the mean of its divisors is an integer number (1638364800).
Almost surely, 213004255051 is an apocalyptic number.
13004255051 is a deficient number, since it is larger than the sum of its proper divisors (102663349).
13004255051 is a wasteful number, since it uses less digits than its factorization.
13004255051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 201289.
The product of its (nonzero) digits is 3000, while the sum is 26.
Adding to 13004255051 its reverse (15055240031), we get a palindrome (28059495082).
The spelling of 13004255051 in words is "thirteen billion, four million, two hundred fifty-five thousand, fifty-one".
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