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130043040021122 = 2243793931367843
BaseRepresentation
bin11101100100011000000001…
…001101001011101010000010
3122001102222211001101220021012
4131210120001031023222002
5114021111121221133442
61140324540423000522
736251204521641554
oct3544300115135202
9561388731356235
10130043040021122
1138487a41971118
1212703266b99142
1357740103c22c7
14241818c3cd4d4
151007ab7dcc582
hex76460134ba82

130043040021122 has 16 divisors (see below), whose sum is σ = 195080398830240. Its totient is φ = 65016240674112.

The previous prime is 130043040021019. The next prime is 130043040021163. The reversal of 130043040021122 is 221120040340031.

It is a super-2 number, since 2×1300430400211222 (a number of 29 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1916789333 + ... + 1916857175.

It is an arithmetic number, because the mean of its divisors is an integer number (12192524926890).

Almost surely, 2130043040021122 is an apocalyptic number.

130043040021122 is a deficient number, since it is larger than the sum of its proper divisors (65037358809118).

130043040021122 is a wasteful number, since it uses less digits than its factorization.

130043040021122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 131537.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 130043040021122 its reverse (221120040340031), we get a palindrome (351163080361153).

The spelling of 130043040021122 in words is "one hundred thirty trillion, forty-three billion, forty million, twenty-one thousand, one hundred twenty-two".

Divisors: 1 2 24379 39313 48758 67843 78626 135686 958411627 1653944497 1916823254 2667111859 3307888994 5334223718 65021520010561 130043040021122