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130043244332 = 2232510811083
BaseRepresentation
bin111100100011100101…
…1100110111100101100
3110102122221022021200202
41321013023212330230
54112312032304312
6135424022013032
712252410224061
oct1710713467454
9412587267622
10130043244332
1150173026251
1221253277178
13c355b35cb1
146419124c68
1535b1a569c2
hex1e472e6f2c

130043244332 has 6 divisors (see below), whose sum is σ = 227575677588. Its totient is φ = 65021622164.

The previous prime is 130043244313. The next prime is 130043244341. The reversal of 130043244332 is 233442340031.

It is a super-2 number, since 2×1300432443322 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130043244295 and 130043244304.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16255405538 + ... + 16255405545.

It is an arithmetic number, because the mean of its divisors is an integer number (37929279598).

Almost surely, 2130043244332 is an apocalyptic number.

It is an amenable number.

130043244332 is a deficient number, since it is larger than the sum of its proper divisors (97532433256).

130043244332 is a wasteful number, since it uses less digits than its factorization.

130043244332 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32510811087 (or 32510811085 counting only the distinct ones).

The product of its (nonzero) digits is 20736, while the sum is 29.

Adding to 130043244332 its reverse (233442340031), we get a palindrome (363485584363).

The spelling of 130043244332 in words is "one hundred thirty billion, forty-three million, two hundred forty-four thousand, three hundred thirty-two".

Divisors: 1 2 4 32510811083 65021622166 130043244332