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130044105553 = 431422971347
BaseRepresentation
bin111100100011100111…
…0111001001101010001
3110102122222221001001211
41321013032321031101
54112312242334203
6135424052300121
712252420441655
oct1710716711521
9412588831054
10130044105553
11501735642aa
1221253611641
13c356077cab
1464192aaa65
1535b1b76c6d
hex1e473b9351

130044105553 has 8 divisors (see below), whose sum is σ = 130378481280. Its totient is φ = 129709881840.

The previous prime is 130044105523. The next prime is 130044105559. The reversal of 130044105553 is 355501440031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130044105553 - 29 = 130044105041 is a prime.

It is a super-2 number, since 2×1300441055532 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130044105559) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1787026 + ... + 1858372.

It is an arithmetic number, because the mean of its divisors is an integer number (16297310160).

Almost surely, 2130044105553 is an apocalyptic number.

It is an amenable number.

130044105553 is a deficient number, since it is larger than the sum of its proper divisors (334375727).

130044105553 is an equidigital number, since it uses as much as digits as its factorization.

130044105553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 76007.

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 130044105553 its reverse (355501440031), we get a palindrome (485545545584).

The spelling of 130044105553 in words is "one hundred thirty billion, forty-four million, one hundred five thousand, five hundred fifty-three".

Divisors: 1 431 4229 71347 1822699 30750557 301726463 130044105553