130044301130441 has 4 divisors (see below), whose sum is σ = 130044581097984. Its totient is φ = 130044021162900.

The previous prime is 130044301130423. The next prime is 130044301130509. The reversal of 130044301130441 is 144031103440031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130044301130441 - 2¹⁰ = 130044301129417 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130044301136441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 139285865 + ... + 140216406.

It is an arithmetic number, because the mean of its divisors is an integer number (32511145274496).

Almost surely, 2^{130044301130441} is an apocalyptic number.

It is an amenable number.

130044301130441 is a deficient number, since it is larger than the sum of its proper divisors (279967543).

130044301130441 is an equidigital number, since it uses as much as digits as its factorization.

130044301130441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 279967542.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 130044301130441 its reverse (144031103440031), we get a palindrome (274075404570472).

The spelling of 130044301130441 in words is "one hundred thirty trillion, forty-four billion, three hundred one million, one hundred thirty thousand, four hundred forty-one".