13005044114443 has 2 divisors, whose sum is σ = 13005044114444. Its totient is φ = 13005044114442.

The previous prime is 13005044114429. The next prime is 13005044114483. The reversal of 13005044114443 is 34441144050031.

13005044114443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13005044114443 - 2¹³ = 13005044106251 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13005044114399 and 13005044114408.

It is not a weakly prime, because it can be changed into another prime (13005044114423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502522057221 + 6502522057222.

It is an arithmetic number, because the mean of its divisors is an integer number (6502522057222).

Almost surely, 2^{13005044114443} is an apocalyptic number.

13005044114443 is a deficient number, since it is larger than the sum of its proper divisors (1).

13005044114443 is an equidigital number, since it uses as much as digits as its factorization.

13005044114443 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46080, while the sum is 34.

Adding to 13005044114443 its reverse (34441144050031), we get a palindrome (47446188164474).

The spelling of 13005044114443 in words is "thirteen trillion, five billion, forty-four million, one hundred fourteen thousand, four hundred forty-three".