Base | Representation |
---|---|
bin | 11000001110010101… |
… | …00100000011100011 |
3 | 1020120100102010011011 |
4 | 30013022210003203 |
5 | 203113302032043 |
6 | 5550252401351 |
7 | 640164424015 |
oct | 140712440343 |
9 | 36510363134 |
10 | 13005111523 |
11 | 5574056858 |
12 | 262b476257 |
13 | 12c3471481 |
14 | 8b52da1b5 |
15 | 511b1159d |
hex | 3072a40e3 |
13005111523 has 4 divisors (see below), whose sum is σ = 13005840448. Its totient is φ = 13004382600.
The previous prime is 13005111461. The next prime is 13005111533. The reversal of 13005111523 is 32511150031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13005111523 - 221 = 13003014371 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13005111494 and 13005111503.
It is not an unprimeable number, because it can be changed into a prime (13005111533) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 337011 + ... + 373612.
It is an arithmetic number, because the mean of its divisors is an integer number (3251460112).
Almost surely, 213005111523 is an apocalyptic number.
13005111523 is a deficient number, since it is larger than the sum of its proper divisors (728925).
13005111523 is an equidigital number, since it uses as much as digits as its factorization.
13005111523 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 728924.
The product of its (nonzero) digits is 450, while the sum is 22.
Adding to 13005111523 its reverse (32511150031), we get a palindrome (45516261554).
The spelling of 13005111523 in words is "thirteen billion, five million, one hundred eleven thousand, five hundred twenty-three".
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