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13005223401 = 34335074467
BaseRepresentation
bin11000001110010101…
…11111010111101001
31020120100121210121210
430013022333113221
5203113314122101
65550255023333
7640165401132
oct140712772751
936510553553
1013005223401
115574122915
12262b50ab49
1312c34b0381
148b5328c89
15511b347d6
hex3072bf5e9

13005223401 has 4 divisors (see below), whose sum is σ = 17340297872. Its totient is φ = 8670148932.

The previous prime is 13005223393. The next prime is 13005223453. The reversal of 13005223401 is 10432250031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13005223401 - 23 = 13005223393 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13005223481) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2167537231 + ... + 2167537236.

It is an arithmetic number, because the mean of its divisors is an integer number (4335074468).

Almost surely, 213005223401 is an apocalyptic number.

It is an amenable number.

13005223401 is a deficient number, since it is larger than the sum of its proper divisors (4335074471).

13005223401 is an equidigital number, since it uses as much as digits as its factorization.

13005223401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4335074470.

The product of its (nonzero) digits is 720, while the sum is 21.

Adding to 13005223401 its reverse (10432250031), we get a palindrome (23437473432).

The spelling of 13005223401 in words is "thirteen billion, five million, two hundred twenty-three thousand, four hundred one".

Divisors: 1 3 4335074467 13005223401