Base | Representation |
---|---|
bin | 11000001110010101… |
… | …11111010111101001 |
3 | 1020120100121210121210 |
4 | 30013022333113221 |
5 | 203113314122101 |
6 | 5550255023333 |
7 | 640165401132 |
oct | 140712772751 |
9 | 36510553553 |
10 | 13005223401 |
11 | 5574122915 |
12 | 262b50ab49 |
13 | 12c34b0381 |
14 | 8b5328c89 |
15 | 511b347d6 |
hex | 3072bf5e9 |
13005223401 has 4 divisors (see below), whose sum is σ = 17340297872. Its totient is φ = 8670148932.
The previous prime is 13005223393. The next prime is 13005223453. The reversal of 13005223401 is 10432250031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 13005223401 - 23 = 13005223393 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13005223481) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2167537231 + ... + 2167537236.
It is an arithmetic number, because the mean of its divisors is an integer number (4335074468).
Almost surely, 213005223401 is an apocalyptic number.
It is an amenable number.
13005223401 is a deficient number, since it is larger than the sum of its proper divisors (4335074471).
13005223401 is an equidigital number, since it uses as much as digits as its factorization.
13005223401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4335074470.
The product of its (nonzero) digits is 720, while the sum is 21.
Adding to 13005223401 its reverse (10432250031), we get a palindrome (23437473432).
The spelling of 13005223401 in words is "thirteen billion, five million, two hundred twenty-three thousand, four hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.203 sec. • engine limits •