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130054255011283 is a prime number
BaseRepresentation
bin11101100100100010011101…
…101010111110010111010011
3122001111001202122101102120011
4131210202131222332113103
5114021302103240330113
61140334033331055351
736252052451534101
oct3544423552762723
9561431678342504
10130054255011283
11384917774a0229
1212705476a41557
1357750a9a21c65
142418933a64c71
15100802278763d
hex76489dabe5d3

130054255011283 has 2 divisors, whose sum is σ = 130054255011284. Its totient is φ = 130054255011282.

The previous prime is 130054255011229. The next prime is 130054255011319. The reversal of 130054255011283 is 382110552450031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130054255011283 - 237 = 129916816057811 is a prime.

It is not a weakly prime, because it can be changed into another prime (130054255011683) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65027127505641 + 65027127505642.

It is an arithmetic number, because the mean of its divisors is an integer number (65027127505642).

Almost surely, 2130054255011283 is an apocalyptic number.

130054255011283 is a deficient number, since it is larger than the sum of its proper divisors (1).

130054255011283 is an equidigital number, since it uses as much as digits as its factorization.

130054255011283 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144000, while the sum is 40.

The spelling of 130054255011283 in words is "one hundred thirty trillion, fifty-four billion, two hundred fifty-five million, eleven thousand, two hundred eighty-three".