Base | Representation |
---|---|
bin | 11101100100100010011101… |
… | …101010111110010111010011 |
3 | 122001111001202122101102120011 |
4 | 131210202131222332113103 |
5 | 114021302103240330113 |
6 | 1140334033331055351 |
7 | 36252052451534101 |
oct | 3544423552762723 |
9 | 561431678342504 |
10 | 130054255011283 |
11 | 384917774a0229 |
12 | 12705476a41557 |
13 | 57750a9a21c65 |
14 | 2418933a64c71 |
15 | 100802278763d |
hex | 76489dabe5d3 |
130054255011283 has 2 divisors, whose sum is σ = 130054255011284. Its totient is φ = 130054255011282.
The previous prime is 130054255011229. The next prime is 130054255011319. The reversal of 130054255011283 is 382110552450031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130054255011283 - 237 = 129916816057811 is a prime.
It is not a weakly prime, because it can be changed into another prime (130054255011683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65027127505641 + 65027127505642.
It is an arithmetic number, because the mean of its divisors is an integer number (65027127505642).
Almost surely, 2130054255011283 is an apocalyptic number.
130054255011283 is a deficient number, since it is larger than the sum of its proper divisors (1).
130054255011283 is an equidigital number, since it uses as much as digits as its factorization.
130054255011283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144000, while the sum is 40.
The spelling of 130054255011283 in words is "one hundred thirty trillion, fifty-four billion, two hundred fifty-five million, eleven thousand, two hundred eighty-three".
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