Base | Representation |
---|---|
bin | 11000001110011101… |
… | …00110100101000110 |
3 | 1020120102101220201020 |
4 | 30013032212211012 |
5 | 203114034423223 |
6 | 5550331212010 |
7 | 640206424152 |
oct | 140716464506 |
9 | 36512356636 |
10 | 13006170438 |
11 | 557470a398 |
12 | 262b8a7006 |
13 | 12c3752451 |
14 | 8b54d4062 |
15 | 511c701e3 |
hex | 3073a6946 |
13006170438 has 16 divisors (see below), whose sum is σ = 26013490416. Its totient is φ = 4335198560.
The previous prime is 13006170409. The next prime is 13006170439. The reversal of 13006170438 is 83407160031.
It is a super-2 number, since 2×130061704382 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13006170399 and 13006170408.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13006170439) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 190348 + ... + 249488.
It is an arithmetic number, because the mean of its divisors is an integer number (1625843151).
Almost surely, 213006170438 is an apocalyptic number.
13006170438 is an abundant number, since it is smaller than the sum of its proper divisors (13007319978).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13006170438 is a wasteful number, since it uses less digits than its factorization.
13006170438 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 95799.
The product of its (nonzero) digits is 12096, while the sum is 33.
The spelling of 13006170438 in words is "thirteen billion, six million, one hundred seventy thousand, four hundred thirty-eight".
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